Q. The orbital angular momentum of an electron in a $d$-orbital is
A) $\sqrt{6}\frac{h}{2\pi}$
B) $\sqrt{2}\frac{h}{2\pi}\$
C) $\frac{h}{2\pi}$
D) $\frac{2h}{2\pi}$
Explanation
(a)
Orbital angular momentum
$(L) = \sqrt{l(l + 1)}\frac{h}{2\pi}$
For $d$-orbital, $l = 2$
$(L) = \sqrt{2(2 + 1)}\frac{h}{2\pi}$
$= \frac{\sqrt{6}h}{2\pi}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.