Q. A body of mass 10 mg is moving with a velocity of 100 $ms^{- 1}$. The wavelength of de-Broglie wave associated with it would be $\left( h = 6.63 \times 10^{- 34}Js \right)$
A) $6.63 \times 10^{- 35}m$
B) $6.63 \times 10^{- 34}m$
C) $6.63 \times 10^{- 31}m$
D) $6.63 \times 10^{- 37}m$
Explanation
(c)
$m = 10\ mg = 10 \times 10^{- 6}kg$
$v = 100\ ms^{- 1}$
$\lambda = \frac{h}{mv} = \frac{6.63 \times 10^{- 34}}{10 \times 10^{- 6} \times 100}$
$\ \ \ = 6.63 \times 10^{- 31}m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.