Q. The valence shell electronic configuration of $Cr^{2 +}$ ion is
A) $4s^{0}3d^{4}$
B) $4s^{2}3d^{2}$
C) $4s^{2}3d^{0}$
D) $3p^{6}4s^{2}$
Explanation
(a)
The ground state configuration of chromium is
$\ _{24}Cr = \lbrack Ar\rbrack 3d^{5}4s^{1}$
$\therefore\ \ \ \ \ _{24}cr^{2 +} = \lbrack Ar\rbrack 3d^{4}4s^{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.