Q. The emission spectrum of hydrogen is found to satisfy the expression for the energy change, $\mathrm{\Delta}E$ (in joules), such that $\mathrm{\Delta}E = 2.18 \times 10^{- 18}\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack$ J, where, $n_{1} = 1,2,3,\ \ldots$ and $n_{2} = 2,3,4,\ldots$ The spectral lines correspond to Paschen series are
A) $n_{1} = 1$ and $n_{2} = 2,3,4$
B) $n_{1} = 1$ and $n_{2} = 3,4,5$
C) $n_{1} = 3$ and $n_{2} = 4,5,6$
D) $n_{1} = 2$ and $n_{2} = 3,4,5$
Explanation
(c)
For Paschen series, $n_{1} = 3$ and $n_{2} = 4,\ 5,\ 6$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.