Q. According to Bohr’s theory, the angular momentum for an electron of 3rd orbit is
A) 3$\ h$
B) $1.5\ h$
C) $9\ h$
D) $2\frac{h}{\pi}$
Explanation
(a)
Angular momentum, $mvr = \frac{nh}{2\pi} = \frac{3 \times h}{2\pi} = \frac{1.5h}{\pi}$
$= 3h\ \ \ \left\lbrack \because h = \frac{h}{2\pi} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.