Q. Uncertainty in the position of an electron $\left( mass = 9.1 \times 10^{- 31}kg \right)$ moving with a velocity 300 $ms^{- 1}$, accurate upon 0.001% will be $\left( h = 6.63 \times 10^{- 34}\ Js \right)$

A) $19.2 \times 10^{- 2}m$
B) $5.76 \times 10^{- 2}m$
C) $1.92 \times 10^{- 2}m$
D) $3.84 \times 10^{- 2}m$
Explanation

(c)
$\mathrm{\Delta}x.\mathrm{\Delta}v \geq \frac{h}{4\pi m}$
$\mathrm{\Delta}x = \frac{6.63 \times 10^{- 34}}{4 \times 3.14 \times 9.1 \times 10^{- 31} \times 300 \times 0.001 \times 10^{- 2}}$
$\ \ \ \ \ \ = 0.01933$
$\ \ \ \ \ \ = 1.93 \times 10^{- 2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.