Q. Correct set of four quantum numbers for valence electron of rubidium ($Z = 37$) is
A) 5,0,0, $+ \frac{1}{2}$
B) $5,1,0, + \frac{1}{2}$
C) $5,1,1, + \frac{1}{2}$
D) $6,0,0, + \frac{1}{2}$
Explanation
(a)
Electronic configuration of $Rb_{(37)}$ is $1s^{2},2s^{2},2p^{6},3s^{2},3p^{6},3d^{10},4s^{2},4p^{6},5s^{1}$
So, for the valence shell electron $5s^{1}$
$n = 5,l = 0,m = 0,s = + \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.