Q. The orbital angular momentum of an electron revolving in a $p$-otbital is
A) Zero
B) $\frac{h}{\sqrt{2\pi}}$
C) $\frac{h}{2\pi}$
D) $\frac{1}{2}\frac{h}{2\pi}$
Explanation
(b)
Orbital angular momentum =$\sqrt{l(l + 1)}\frac{h}{2\pi}$
For $p$-orbital, $l = 1$
∴ Orbital angular momentum
$= \sqrt{1(1 + 1)}\frac{h}{2\pi} = \frac{\sqrt{2}h}{2\pi}$
$= \frac{h}{\sqrt{2}\pi}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.