Explanation

(c)
According to rules of quantum number the possible values of $n,l,m\ and\ s\ are$
$n = 1$ to $\infty$ any whole number
$l = 0$ to $(n - 1)$ for every value of $n$
$m = - l$ to zero to $+ l$ for every value of $l$
$s = \frac{1}{2}or - \frac{1}{2}$
$n = 4,\ l = 3,\ m = 0$
All the values are according to rules.
$n = 4,\ l = 2,\ m = 1$
All the values are according to rules.
$n = 4,\ l = 4,\ m = 1$
$\because$The value of $l$ can have maximum $(n - 1)$value $i.e$., 3 in this case.
∴ This set of quantum numbers is non-permissible.
$n = 4,\ l = 0,\ m = 0$
All the values are according to rules.
∴ Choice (a), (b) and (d) are permissible.