Q. The increasing order (lowest first) of the value of $\frac{e}{m}$ for electron $(e)$, proton $(p),$neutron $(n)$ and alpha particle $(\alpha)$ will be
A) $n,\alpha,p,e$
B) $e,p,n,\alpha$
C) $n,p,e,\alpha$
D) $n,p,\alpha,e$
Explanation
(a)
$\frac{e}{m}$ for : (i) neutron $= \frac{0}{1} = 0$
(ii)$\alpha$-particle $= \frac{2}{4} = 0.5$
(iii)proton $= \frac{1}{1} = 1$
(iv)electron $= \frac{1}{1/1837} = 1837$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.