Q. The incorrect statement about Bohr’s orbit of hydrogen atom is
A) $r = n^{2}\frac{h^{2}}{4\pi^{2}m\left( \frac{e^{2}}{4\pi\varepsilon_{0}} \right)}$
B) KE of electron = PE of electron
C) $E = - \frac{1}{n^{2}}\frac{2\pi^{2}m\left( \frac{e^{2}}{4\pi\varepsilon_{0}} \right)^{2}}{h^{2}}$
D) None of the above is incorrect
Explanation
(b)
In Bohr orbit,
KE of $e^{-} = \frac{1}{2}\frac{Zke^{2}}{r_{n}}$
PE of $e^{-} = \frac{Zke^{2}}{r_{n}}$
Thus, KE$= - \frac{1}{2}\$PE
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.