Q. A particle having a mass of 1.0 mg has a velocity of 3600 km/h. Calculate the wavelength of the particle $\left( h = 6.626 \times 10^{- 27}erg - s \right)$
A) $6.626 \times 10^{- 28}cm$
B) $6.626 \times 10^{- 29}cm$
C) $6.626 \times 10^{- 30}cm$
D) $6.626 \times 10^{- 31}cm$
Explanation
(b)
$\lambda = \frac{h}{mv}$
Here, $v = 3600\ km/h$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 10^{5}cm/s$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ m = 1.0mg = 10^{- 3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda = \frac{6.626 \times 10^{- 27}}{10^{- 3} \times 10^{5}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 6.626 \times 10^{- 29}cm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.