Q. Among the following series of transition metal ions, the one in which all metal ions have $3d^{2}$ electronic configuration is (At. no. Ti=22, V=23, Cr=24, Mn=25)
A) $Ti^{3 +},\ V^{2 +},Cr^{3 +},Mn^{4 +}$
B) $Ti^{+},V^{4 +},Cr^{6 +},Mn^{7 +}$
C) $Ti^{4 +},V^{3 +},Cr^{2 +},Mn^{3 +}$
D) $Ti^{2 +},V^{3 +},Cr^{4 +},Mn^{5 +}$
Explanation
(d)
$Ti^{2 +} = 1s^{2},2s^{2}2p^{6},3s^{2}3p^{6}3d^{2},4s^{0}$
$V^{3 +} = 1s^{2},2s^{2}2p^{6},3s^{2}3p^{6},3d^{2},4s^{0}$
$Cr^{4 +} = 1s^{2},2s^{2}2p^{6},3s^{2}3p^{6}3d^{2},4s^{0}$
$Mn^{5 +} = 1s^{2},2s^{2}2p^{6},3s^{2}3p^{6}3d^{2},4s^{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.