Q. The orbital angular momentum of an electron in $2s$ orbital is
A) $+ \frac{1}{2}.\frac{h}{2\pi}$
B) Zero
C) $\frac{h}{2\pi}$
D) $\sqrt{2}\frac{h}{2\pi}$
Explanation
(b)
Orbital angular momentum
$= \sqrt{l(l + 1)}.\frac{h}{2\pi}$
For 2$s$-orbital, $l = o$
∴ Orbital angular momentum
$= \sqrt{0(0 + 1)}\frac{h}{2\pi} = zero$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.