Q. Energy of photon of visible light is
A) 1 eV
B) 1 MeV
C) 1 eV
D) 1 keV
Explanation
(a)
$\lambda$ for visible light is in the range of 400 to 780 nm.
$E = \frac{hc}{\lambda}.$
This, it is in the range of electron volt (eV).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.