Q. For a Bohr atom angular momentum $M$ of the electron is ($n = 0,\ 1,\ 2,\ldots$)
A) $\frac{nh^{2}}{4\pi}$
B) $\frac{n^{2}h^{2}}{4\pi}\$
C) $\frac{\sqrt{\pi h^{2}}}{4\pi}$
D) $\frac{nh}{2\pi}$
Explanation
(d)
Angular momentum of electrons $= mvr = \frac{nh}{2\pi}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.