Q. A body of mass $x$ kg is moving with a velocity of $100ms^{- 1}$. Its de-Broglie wavelength is $6.62 \times 10^{- 35}$m. Hence, $x$ is ($h = 6.62 \times 10^{- 34}Js$)
A) 0.1 kg
B) 0.25 kg
C) 0.15 kg
D) 0.2 kg
Explanation
(a)
$\lambda = \frac{h}{mv}$
$= \frac{6.62 \times 10^{- 34}}{6.62 \times 10^{- 35} \times 100}$
$= 0.1\ kg$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.