Q. The relationship between the energy $E_{1}$ of the radiation with a wavelength 8000Å and the energy $E_{2}$ of the radiation with a wavelength 16000Å is
A) $E_{1} = 6E_{2}$
B) $E_{1} = 2E_{2}$
C) $E_{1} = 4E_{2}$
D) $E_{1} = 1/2E_{2}$
Explanation
(b)
$E = \frac{hc}{\lambda},h\ and\ c$ for both causes are same so,
$\frac{E_{1}}{E_{2}} = \frac{\lambda_{2}}{\lambda_{1}} = \frac{16000}{8000}$
$E_{1} = 2E_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.