(a)
$1s^{2},2s^{2},2p^{6},3s^{1}$configuration represents the Na, because the atomic number of Na is 11. The first ionisation energy is less than second ionisation energy because $IE_{2}$involves the removal of an electron from the stable configuration ($i.e.,\ 1s^{2},2s^{2},2p^{6})\$