Q. The electron affinity values (in $kJ\ mol^{- 1}$) of three halogens $X$,$Y$ and $Z$ are respectively $- 349,\ - 333$ and $- 325$. Then $X$, $Y$ and $Z$ respectively, are
A) $F_{2},Cl_{2}and\ Br_{2}$
B) $Cl_{2},\ F_{2}\ and\ Br_{2}$
C) $Cl_{2},\ Br_{2}\ and\ F_{2}$
D) $Br_{2},Cl_{2}and\ F_{2}$
Explanation
(b)
The electron affinity (in kJ/mol)
Fluorine=332.6
Chlorine=348.5
Bromine=324.7
Iodine=295.5
Chlorine has highest electron affinity value, so, according to question the correct order of electron affinity will be $Cl_{2} > F_{2} > Br_{2}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.