Q. The ionic radius of ‘Cr’ is minimum in which of the following compounds?
A) $CrO_{2}$
B) $K_{2}CrO_{4}$
C) $CrF_{3}$
D) $CrCl_{3}$
Explanation
(b)
In $K_{2}CrO_{4},$ the oxidation state of Cr is +6. Therefore, Cr has the minimum radius in $K_{2}CrO_{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.