Q. If the electronegativity difference between two atoms $A$ and $B$ is 2.0, then the percentage of covalent character in the molecule is
A) 54%
B) 46%
C) 23%
D) 72%
Explanation
(b)
According to Hannay and Smith equation
$\therefore\%\$ionic character
=16$\left( x_{A} - x_{B} \right) + 3.5\left( x_{A} - x_{B} \right)^{2}$
Where, $x_{A}\$and $x_{B}$are the electronegative of the atoms $A$ and $B$ respectively.
$\therefore\ \%\ ionic\ charecter = 16(2) + 3.5(2)^{2}$
=32+14=46%
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.