(d)
Fluorine has maximum reduction electrode potential $(E{^\circ}_{F/F^{-}})$ =2.87 V, hence, it is easily reduced into $F^{-}$and consequently $F_{2}$is the best oxidising agent.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.