Q. The $I^{st}$ IEs of four consecutive elements present in the second period of Periodic Table are 8.3, 11.3, 14.5 and 13.6 eV respectively. Which of these is the IE of nitrogen?
A) 13.6
B) 8.3
C) 14.5
D) 11.3
Explanation
(c)
Generally in a period, IE increases but nitrogen due to the presence of half-filled $p$-subshell (stable configuration) has higher IE as compared to its consecutive elements. Thus, the IE of nitrogen is 14.5
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.