(d)
$\ _{20}Ca = \lbrack Ar\rbrack 4s^{2}$
$\ \ _{21}Sc = \lbrack Ar\rbrack 4s^{2},3d^{1}\$
$\ _{22}Ti = \lbrack Ar\rbrack 4s^{2},3d^{2}$
As $d$-orbital have diffused shape, hence their electron shields nuclear charge upto lesser extent. Hence, due to increase in effective nuclear charge $(Z_{eff})$ atomic size decrease, in the following order
$Ca > Sc > Ti$