Q. The electronic configuration of the atom having maximum difference in first and second ionisation energies is
A) $1s^{2},2s^{2},2p^{6},3s^{1}$
B) $1s^{2},2s^{2},2p^{6},3s^{2}$
C) $1s^{2},2s^{2},2p^{1}$
D) $1s^{2},2s^{2},2p^{6},3s^{2},3p^{1}$
Explanation
(a)
Ionisation energy defined as the energy required to remove an electron from the outermost orbit of an isolated gaseous atom in its ground state.
Na(11)$= 1s^{2},2s^{2},2p^{6},3s^{1}$
$Na \rightarrow Na^{+} + e^{-}(First\ IE)$
$Na^{+} \rightarrow Na^{2 +} + e^{-}(Second\ IE)$
First IE is lower and second IE is very higher, because removal of an electron from $Na^{+}$is very difficult.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.