Q. Chlorine atom, in its third excited state, reacts with fluorine to form a compound X. The formula and shape of X are
A) $ClF_{5},$ pentagonal
B) $ClF_{4}$, tetrahedral
C) $ClF_{4}$, pentagonal bipyramidal
D) $ClF_{7}$, pentagonal bipyramidal
Explanation
(d)
7Cl=$1s^{2},2s^{2},2p^{6},3s^{2},3p_{x}^{2},3p_{y}^{2},3p_{z}^{1}$
Cl=$1s^{2},2s^{2},2p^{6},3s^{1},3p_{x}^{1},3p_{y}^{1},3p_{z}^{1},3d^{1},3d^{1}3d^{1}$
(3rd excited state)
Chlorine atom, in its third excited state, reacts with fluorine to form $ClF_{7}$. Its shape is pentagonal bipyramidal.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.