Q. Be in $BeCl_{2}$ undergoes
A) Diagonal hybridisation
B) Trigonal hybridisation
C) Tetrahedral hybridisation
D) No hybridisation
Explanation
The correct answer is Option A: Diagonal hybridisation.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.