Q. If the molecule of HCl were totally polar, the expected value of dipole moment is 6.12 D (dbye), but the experimental value of dipole moment was 1.03 D. Calculate the percentage ionic character
A) 17
B) 83
C) 50
D) Zero
Explanation
(a)
Percentage ionic character
$= \frac{experimental\ value\ of\ DM}{theoretical\ value\ of\ DM} \times 100$
$= \frac{1.03}{6.12} \times 100 = 17\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.