Explanation

(c)
Sulphur is $sp^{2}$hybridised in $SO_{2}$.
$S = 1s^{2},2s^{2}2p^{6},\ 3s^{2}3p^{4}3d^{0}$
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Due to $sp^{2}$-hybridisation and presence of one lone pair of electrons $SO_{2}$ has angular geometry.
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Among $N_{2}O,\ CO_{2}\ and\ CO,\$ all have $sp$-hybridisation.