If $Na^{+}$ ion is larger than $Mg^{2 +}$ ion and $S^{2 -}$is larger than$Cl^{-}$ ion, which of the following will be stable soluble in water?

Question

Dr. Abubacker · Accepted Answer

(d)
Higher the lattice energy lower the solubility. Out of the four combinations possible, the lattice energy of MgS (bi-bivalent ionic solid) is higher than those of $Na_{2}S,\ MgCl_{2}$ (uni-bivalent or biuni-valent ionic solids ) and NaCl (uni-univalent ionic solids) and hence, MgS is the least soluble.

Q. If $Na^{+}$ ion is larger than $Mg^{2 +}$ ion and $S^{2 -}$is larger than$Cl^{-}$ ion, which of the following will be stable soluble in water?

Explanation

Reviewed by Dr. Abubacker

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