Q. The electronic configuration of four elements $L,P,Q\$and$\ R$ are given in brackets $L\left( 1s^{2},2s^{2},2p^{4} \right),P\left( 1s^{2},2s^{2},2p^{6},3s^{1} \right),Q\left( 1s^{2},2s^{2},2p^{6},3s^{2},3p^{5} \right),\ R(1s^{2},2s^{2},2p^{6},3s^{2})$ The formula of ionic compounds that can be formed between these elements are
A) $L_{2}p,RL,PQ\$and$R_{2}Q$
B) $LP,RL,PQ\$and$\ RQ$
C) $P_{2}L,RL,PQ\$and$\ RQ_{2}$
D) $LP,R_{2}L,P_{2}Q,\$and$\ RQ$
Explanation
(c)
Valencies of $L,Q,P$ and $R$ is-2,-1,+1, and +2 respectively. So, they will form $P_{2}L,RL\ PQ,\$and$\ RQ_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.