Q. $sp^{3}\ d$ hybridisation results in
A) A square planar molecule
B) An octahedron molecule
C) A trigonal bipyramidal molecule
D) A tetrahedron molecule
Explanation
(c)
$sp^{3}\$hybridisation Tetrahedron molecule
$dsp^{2}\$hybridisation Square planar molecule
$sp^{3}d\$hybridisation Trigonal bipyramidal molecule
$sp^{3}d^{2}\ or\ d^{2}{sp}^{3}\$ Octahedron molecule
hybridisation
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.