Q. In the molecule $CH \equiv C - CH = CH_{2}$, the hybridisation of C – C bond is
A) $sp^{2} - \ sp$
B) $sp^{3} - \ sp^{3}$
C) $sp^{2} - \ sp^{2}$
D) $sp^{3} - sp$
Explanation
(a)
$sp\ \ \ \ \ \ \ sp\ \ \ \ sp^{2}\ \ \ \ sp^{2}$
$CH \equiv C - CH = CH_{2}$
Hence, carbon atom bonded to each other by single
$(C - C)$ are $sp$ and $sp^{2}\ hybrid.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.