Q. The electronegativity of A and B are 1.20 and 4.0 respectively. Therefore, ionic character in $A - B$ bond will be
A) 50%
B) 43%
C) 53.3%
D) 72.23%
Explanation
(d)
Ionic character$= 16\left( E_{A} - E_{B} \right) + 3.5\left( E_{A} - E_{B} \right)^{2}$
$= 16(4 - 1.2) + 3.5(4 - 1.2)^{2}\$
$= 72.24\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.