Q. Which of the following has $sp^{2}$ hybridisation?

A) $C_{2}H_{6}$
B) $C_{2}H_{4}$
C) $BeCl_{2}$
D) $C_{2}H_{2}$
Explanation

(b)
In $C_{2}H_{6},C\$is$\ sp^{3}\$hybridised$.$
In $C_{2}H_{4},C\$is$\ sp^{2}\$hybridised$.$
In $Be{Cl}_{2},Be\$is$\ sp\$hybridised$.$
In $C_{2}H_{2},C\$is$\ sp\$hybridised

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.