(c)
Given, ionic charge $= 4.8 \times 10^{- 10}$ esu
and, ionic distance $= 1\ \mathring{\mathrm{A}} = 10^{- 8}$cm
We know that
Dipole moment $=$ionic charge$\times$ionic distance
$= 4.8 \times 10^{- 10} \times 10^{- 8}$
$= 4.8 \times 10^{- 18}$ esu $cm^{- 1}$
$= 4.8$ debye