Q. Geometry of ammonia molecule and the hybridisation of nitrogen involved in it are
A) $sp^{3}$ hyridisation and tetrahedral geometry
B) $sp^{3}$ hyridisation and distorted tetrahedral geometry
C) $sp^{2}$ hyridisation and triangular geometry
D) None of the above
Explanation
(b)
(i) Hybridisation =$\frac{1}{2}$ (no. of $e^{-}$ in valence shell of central atom + no. of monovalent atoms + charge on anion – charge on cation)
(ii) Shape or geometry of molecule depends on lone pair and bond pair of electrons present in it.
Hybridisation of
N in $NH_{3}$ $= \frac{1}{2}\ (5 + 3 + 0 - 0) = 4$
$\therefore\ \ sp^{3}$ hybridisation.
$\because$ It has 3 bond pair and 1 lone pair of electrons, so it has distorted tetrahedron shape.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.