(d) $BCl_{3} = 3\sigma\$bonds$+ 0lp\$of$\ e^{-} = 3 \Longrightarrow sp^{2}$hybridisation $NCl_{3} = 3\sigma\$bonds$+ 1lp\$of$\ e^{-} = 4 \Longrightarrow sp^{3}$hybridisation
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Ph.D. in Physics with 19+ years of teaching experience.