(a)
In ($A$) $para$-nitro phenol intermolecular (between two molecules) H-bonding exists while in ($B$) $ortho$ –nitrophenol, intramolecular H-bonding exists.
Because of the presence of intramolecular H-bonding, the boiling point of ($B$) is lower as compare to ($A$) and thus, ($B$) is more volatile $i.e$., has higher vapour pressure as compare to ($A$).