Explanation

(d)
$BCl_{3}$ has bond angle equal to $120{^\circ}$ (trigonal planar). $NH_{3}$ and $H_{2}O$ have $sp^{3}$ hybridisation but due to the presence of lone pair of electrons, they have bond angle less than ${109.28}^{'}\left( NH_{3} - \ 107{^\circ},\ H_{2}O - 104.5{^\circ} \right),\ AsH_{3}\ (sp^{3}\$hybrid$)$ has smaller bond angle than $NH_{3}$ due to less electronegativity of As than N.