Q. If $H - X$ bond length is $2.00\ \mathring{\mathrm{A}}$ and $H - X$ bond has dipole moment $5.12 \times 10^{- 30}\ C - m$, the percentage of ionic character in the molecule will be
A) $10\%$
B) $16\%$
C) $18\%$
D) $20\%$
Explanation
(b)
Calculated dipole moment,
$\mu_{cal} = 2.0 \times 10^{- 10}\ m \times 1.6 \times 10^{- 19}\ C$
$= 3.2 \times 10^{- 29}\ C - m.$
Percentage of ionic character = $\frac{\mu_{\exp}}{\mu_{cal}} \times 100$
$\ = \frac{5.12 \times 10^{- 29}}{3.2 \times 10^{- 29}} \times 100 = 16\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.