Q. $H_{2}O$ is dipolar, whereas $BeF_{2}$ is not. It is because
A) The electronegativity of F is greater than that of O
B) $H_{2}O$ involves hydrogen bonding whereas $BeF_{2}$ is a discrete molecule
C) $H_{2}O$ is linear and $BeF_{2}$ is angular
D) $H_{2}O$ is angular and $BeF_{2}$ is linear
Explanation
(d)
The structure of $H_{2}O$ is angular V-shape and has $sp^{3}$- hybridisation and bond angle is $105{^\circ}$. Its dipole moment value is positive or more than zero.
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But in $BeF_{2}$ , structure is linear due to $sp$- hybridisation $(\mu = 0)$. Thus, due to $\mu > 0,$ $H_{2}O$ is dipolar and due to $\mu = 0$, $BeF_{2}$ is non-polar.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.