Q. Consider the following compounds (i) chloroethene (ii) benzene (iii) 1, 3-butadiene (iv) 1,3,5 – hexatriene All the carbon atoms are $sp^{2}$ hybridised in
A) (i), (iii), (iv) only
B) (i), (ii) only
C) (ii), (ii), (iv) only
D) (i), (ii), (iii) and (iv)
Explanation
(d)
[image:4_image141.emf] all carbon atoms are $sp^{2}$ hybridised chloroethene
$CH_{2} = CH - CH = CH_{2}$
$sp^{2}\ \ \ \ \ \ \ sp^{2}\ \ \ \ sp^{2}\ \ \ \ \ sp^{2}$
$CH_{2} = CH - CH = CH - CH = CH_{2}$
$sp^{2}\ \ \ \ \ \ \ sp^{2}\ \ \ \ sp^{2}\ \ \ \ sp^{2}\ \ \ \ \ sp^{2}\ \ \ \ \ \ sp^{2}\ \ \ \$
1, 3, 5-hexatriene
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.