Q. From the molecular orbital theory, one can show that the bond order in $F_{2}$ molecule as
A) 2
B) 1
C) 3
D) 4
Explanation
(b)
According to molecular orbital theory.
$F_{2}(18) = \ \sigma 1s^{2},\ _{\sigma}^{*}1s^{2}\ ,\sigma 2s^{2},\ _{\sigma}^{*}2s^{2},\sigma 2p_{z}^{2}\ ,\ \pi 2p_{x}^{2} \approx \pi 2p_{y}^{2}{,\ }_{\pi}^{*}2p_{x,}^{2} \approx \ _{\pi}^{*}2p_{y}^{2}$
Bond order in $F_{2}$= $\frac{N_{b - \ }N_{a\ }}{2} = \frac{10 - 8}{2} = 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.