Q. An atom of an element A has three electrons in its outermost orbit and that of B has six electrons in its outermost orbit. The formula of the compound between these two will be
A) $A_{3}B_{6}$
B) $A_{2}B_{3}$
C) $A_{3}B_{2}$
D) $A_{2}B$
Explanation
(b)
A three electrons in its outermost orbit, its valency is 3. B has six electrons in its outermost orbit, its valency is 2
Element
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Valency
Formula of the compound = $A_{2}B_{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.