Q. The compound in which underlined carbon uses only its $sp^{3}$ hybrid orbitals for bond formation is
A) $CH_{3}\underline{C}OOH$
B) $CH_{3}\underline{C}ONH_{2}$
C) $CH_{3}\underline{C}H_{2}OH$
D) $CH_{2}\underline{C}H = CH_{2}$
Explanation
(c)
$O$ $O$
$||$ $||$
$CH_{3} - C - OH$ $CH_{3} - C - {NH}_{2}$
$sp^{2}$ $sp^{2}$
$O$ $H$
$||$ $|$
$CH_{3} - C - OH$ $CH_{3} - C - {CH}_{2}$
$\ |$ $sp^{2}$
$\ H$
$sp^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.