Q. In which of the following compound $sp^{2}$ hybridisation is absent?
A) $CH_{2} = CH - CH = CH_{2}$
B) $CH \equiv C - CH_{2} - CH_{3}$
C) $CH_{2} - CH = CH_{2}$
D) $CH_{2} = CH - CH_{2} - CH_{3}$
Explanation
(b)
$CH \equiv C - CH_{2} - CH_{3}$
$sp\ \ \ \ \ sp\ \ \ \ \ \ sp^{3}\ \ \ \ \ \ sp^{3}$
In butyne – 1, there is no carbon with $sp^{2}$ hybridisation.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.