(b)
Due to intermolecular hydrogen bonding in $ortho$-isomer, it has least melting point. Due to effective intermolecular hydrogen bonding in $para$ isomer, it has highest melting point among the isomers. So, the order is
$Para$ isomer > $meta$ > $ortho$
$\ \ \ (114℃)\ \ \ \ \ \ \ \ \ (97℃)\ \ \ (54\ ℃\ )$