Q. The electronic configuration

can be assigned to

A) $O_{2}$
B) $O_{2}^{+}$
C) $O_{2}^{-}$
D) $O_{2}^{2 -}$
Explanation

(c)
The molecular orbital electronic configuration.
$\ _{(\sigma 1s)^{2}(\sigma\ 1{s)}^{2}(\sigma 2s)^{2}}^{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ *}\ _{(\sigma\ 2{s)}^{2}\left( \sigma 2p_{x} \right)^{2}}^{\ \ \ *}$
$\ _{{\left( \pi 2p_{y} \right)^{2}\left( \pi 2p_{z} \right)^{2}\left( \pi 2p_{y} \right)}^{2}\ \ }^{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ *}\ _{\left( \pi 2p_{z} \right)^{1}\ \ }^{\ \ *}$
Total electrons =17
Hence, this configuration belongs to $O_{2}^{-}$ (17$e^{-})$ ion.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.